what is the identity of the metal chloride?

The temperature of the water decreased by 0.93 oC. Given that the cation is from Group 1A, what is the identity of the group 1A metal ion in your solution? A 2.5624-g sample of a pure solid alkali metal chloride is dissolved in water and treated with excess silver nitrate. For instance sodium chloride has a mass percent of around 60% chloride. Identify the metal. Copper is one of the least reactive metals. Copper and zinc atoms are different sizes. What is the identity of the salt? As well as to identify unknown metallic ions by means of its flame test. The student then mixes the solution with excess AgNO3 solution, causing the AgCl to precipitate. 23. softer (1) (b) Iron chloride has the formula FeCl 3 Relative atomic masses (Ar): Cl = 35.5; Fe = 56. To find the percentage of the metal, first determine the difference between the mass of the compound and the mass of chlorine. analyzed to determine the identity of the metal. The moles of calcium carbonate, CaCO3, are equal to the moles of Group 1 metal carbonate, M2CO3, added to the original solution. After teh precipitate had been filtered and dried, it weighed 0.2327 g. Specific questions: 1. M + (2 x 16.00) + (2 x 1.01) M + 34.02. The chloride of an unknown metal is believed to have the formula $\mathrm{MC We obtained this identity through reacting the unknown chloride-containing solute with silver nitrate in acidic conditions to form a silver chloride precipitate. Answer (1 of 5): It will be a double displacement reaction leading to the formation of sparingly soluble magnesium hydroxide as a white precipitate. strontium chloride. M 2CO 3(s) 2M+(aq) + CO 3 2-(aq) Equation 1 When a solution of calcium chloride, CaCl 2, is added to this metal carbonate solution, a These halide ion compounds exist in different forms in nature as solutions, precipitates and solids. Homework Equations current*time=coulombs coulombs/96486=faraday Dividing the mass of the unknown carbonate by the moles of calcium carbonate yields the formula weight, and thus the identity, of the Group 1 metal carbonate. Magnesium chloride has an even higher mass percent of chloride in it at 74%. What is the identity of the metal chloride? Given the stoichiometry of the precipitation reaction, there were (2.51xx10^-2*mol)/2 = 1.26xx10^-2*mol MCl_2. sodium chloride/potassium . Percentage of chlorine by mass = 63.89 So, percentage of M by mass in MCl2 = 100 - 63.89 = 36.11 Atomic ratio of M and chlorine (Cl) in one formula unit of MCl2 = 1 : 2 Atomic weight of chlorine = 35.46 Let the atomic weight of M be 'A'. Some halide compounds have colours which is useful to identify them. The specific heat of a metal was found to be 0.38 J/g*C. This will contain the same number of moles of Ag+ and because the precipitate is AgCl, it will also be the same as the number of moles of Cl- (from the metal chloride). Method 2: Take the nichrome or platinum wire and create a small loop at the end by bending the wire. The flame test is a qualitative test used in chemistry to help determine the identity or possible identity of a metal or metalloid ion found in an ionic compound. What is the identity of metal chloride? An unknown metal hydroxide (X(OH)2) is titrated with 100.0 mL of 2.00 M sulfuric acid to precipitate 46.7 g of the metal sulfate (XSO4). Given that the ionic compound contains either chloride or hydroxide, how can you determine which? Still another metal-specific effect of subchronic Me-NP intoxications considered in Section 3.1 is an increased reticulocyte percentage under the impact of PbO-NPs (24.7 2.7 against 10.2 1.4 in control rats, P < 0.05). Divide the mass of the metal by the total mass of the compound and multiply by 100. If Cl=35.5, find the mass of this number of moles of Cl- ions and subtract this to find the mass of M in 20.0g of MCl. Include states (s, l, g, aq). None of the other halides behave like Cl - in this reaction. Na+ + Cl-. School Schoolcraft College; Course Title CHEM 104; Uploaded By MateEnergyCaribou19. Write the full equation for the double replacement reaction that occurs between the calcium chloride and the metal carbonate in solution. harder This makes brass more flexible than the pure metals. 3. Now that you have identified the unknown metal in the metal carbonate, write the equation for the metal carbonate dissolving in water. Conduct tests of the reacting system to determine the identity of the ions forming the precipitate. Include states. Strontium chloride (SrCl2) is a salt of strontium and chloride. So we have a molar quantity, and a given mass, and the "molecular mass . "41.65 g"-"14.18 g"="27.47 g" The mass of the metal in the compound is . 2(IIA) Because The elements in Group 2 (IIA) are metals with a +2 oxidation state. X(OH)2 + H2SO4 2H2O + XSO4 Write an ionic equation, including state symbols, for the reaction that takes place when sulfuric acid is added to solution Y . (The molar mass of AgCl is 143 g/mol) Halide compounds of Pb and Ag have colours. Likewise, tin is going from a 2+ oxidation state in tin(II) chloride to being precipitated as tin metal. Conclusion : From this experiment, we determined the identity of a chloride-containing solute to be sodium chloride (NaCl). potassium chloride. Observe and record the "signs" of a chemical reaction when aluminum metal is added to a solution of copper(II) chloride. (i) Calculate the relative formula mass ( Mr) of iron chloride (FeCl3). . By determining the mass of the silver chloride, we were able . 330 J. By comparing the color given off by an unknown with the known metal salts, the identity of the metal salt can be determined. calcium chloride. Copper (II) chloride, also known as cupric chloride, is a inorganic salt used as catalysts in chemical synthesis and is also used in the manufacturing of pyrotechniques for its blue/green colors. Wear . The student collects the precipitate by filtration, dries it, and records the data shown below. If appropriate they can be told that this gas is hydrogen. This only means that the X has a charge of +2 since there are 2 Cl in the compounds. Answer (1 of 2): Equivalent weight = weight of the metal/ weight of chlorine 35.5 = 29/71 35.5 = 14.5 Valency =2vapourdensity/( E+35.5 ) = 2 Equivalent weight valency = Atomic weight =14.52 =29 Therefore atomic weight = 29 (Two pieces. Thus one atom of a Group 2 metal can combine with 2 atoms of chlorine (oxidation state = -1) Since MCl2 is described as a salt, M is most likely to be a bivalent metal. This has been known for a long time and . If the compound contains 65.57% Cl by mass, what is the identity of the metal? A metal M forms a compound with the formula MCl 4.If the compound is 74.75% chlorine, what is the identity of M? 2. Copper and zinc atoms are different sizes. They dissolved a 0.1472-g sample of the salt in water adn treated it with excess barium chloride, resulting in the precipitation of barium sulfate. Pages 4 Ratings 33% (3) 1 out of 3 people found this document helpful; What is the identity of the metal M? Get solutions Get solutions Get solutions done loading Looking for the textbook? Advertisement. The chloride of a metal (M) contains 65.5% of chlorine. This will give the mass of the metal. Formula and structure: Copper (II) chloride chemical formula is CuCl 2 and the molar mass is 134.45 g mol -1. 5. The specific heat capacity of the solution is 4.184 J/goC. In the molecule of your unknown compound you have three atoms of fluorine, this means that in one mole of this compound you have 57 g of fluorine (from 19.0 x 3) that represent 49.2% by weight. chemistry Describe the evidence (observations) supporting the formation of solid copper metal in this reaction. One mole of unknown compound weighs (57/0.492) = 115.85 g. Knowing that 57 g are made by fluorine, the unknown atom will count for 58.85 g in each mole. Identify the most reasonable alkaline metal chloride compounds for the identity. Work out moles AgNO3 using volume in L x molarity. What is the identity of the alkaline earth metal chloride? In . "Molar mass of metal chloride" = 126.2*g*mol^-1 We need a stoichiometric equation: MCl_2(aq) + 2AgNO_3(aq) rarr M(NO_3)_2(aq) + 2AgCl(s)darr "Moles of silver chloride:" = (3.60*g)/(143.32*g*mol^-1)=2.51xx10^-2*mol. Chlorine gas has characteristic odour, colour and bleaching properties. Halides ions are fluorides chloride, bromide, and iodide. I m. C 03 has a mass of It's a 2.395 gram sample, and, uh, we're told that chlorine is present in 1.28 grams, so metal em has a massive 1.115 grabs. Note the test solutions are the same concentration (0.10 M) as that in the reacting system under analysis. MgCl2 (aq) + 2NaOH (aq) Mg(OH)2 (s) + 2NaCl (aq) The other product, sodium chloride, remains in solution. In other words, the tin(II) cations act as an oxidizing agent because they . When 0.5007 g of this metal was heated in a stream of chlorine gas, it produced 1.0586 g of a metal chloride, MClx. Non-metals are formed at the positive electrode: chloride ions produce gaseous chlorine bromide and iodide ions form bromine and iodine respectively which dissolve to form coloured solutions. After identifying the chloride salt in the sample, calculate the amount (mL) of .2M solution of silver nitrate assuming it is 100% pure. What is the identity of m? Chromyl chloride (CrO 2 Cl 2) test is a unique test to identify Chloride ions. What is the identity of m2co3? softer (1) (b) Iron chloride has the formula FeCl 3 Relative atomic masses (Ar): Cl = 35.5; Fe = 56. Given that the ionic compound contains either chloride or hydroxide, how can you determine which? An unknown metal hydroxide (X(OH)2) is titrated with 100.0 mL of 2.00 M sulfuric acid to precipitate 46.7 g of the metal sulfate (XSO4). A gas is evolved at the negative electrode if the metal is high in the reactivity series. Light the Bunsen burner. In addition, identical volumes (5 mL) are combined for . Solution #1: 1) Write an expression for the molar mass of the compound: Let M = the molar mass of the metal. Be as specific as possible! CH 4 (g) + 2 O 2 (g) CO 2 (g) + 2 H 2 O (g) All of the following statements concerning this reaction are correct EXCEPT. A student dissolves the chloride of the unknown metal, MCl, in water to make it 100.0 mL of solution. Na+ (aq) + C2O42- (aq) / Ca2+ + C2O42-. 4. a. Its chemical properties are intermediate between those for barium chloride, which is more toxic, and calcium chloride. of evidence are required and one must be related to solubility rules) 3. Name the precipitate. harder This makes brass more flexible than the pure metals. X(OH)2 + H2SO4 2H2O + XSO4 1. a) two moles of water are formed per one mole of methane consumed. Purpose: The purpose of this lab was to observe the characteristic colors produced by certain metallic ions when vaporized in a flame. M+ is an unknown metal cation with a +1 charge. Solutions (1.0 mol/L) of the following metal salts . lithium chloride. A metal M forms a compound with the formula MCl 4.If the compound is 74.75% chlorine, what is the identity of M? . 2. The heat capacity of the calorimeter is 42.2 J/oC. X +2 + Cl - --> XCl 2 3. Answer $\mathrm{M}=55.84 \mathrm{g} / \mathrm{mol}$ . Unknown salt could be any of the four: NiCl2 or NaCl or KCl or BaCl2.2H2O Write the molecular equation of the reaction. Dip the loop into the lithium salt solution. 1 Three Students were asked to find the identity of the metal in a particular sulfate salt. Turn the collar on the Bunsen burner so that you have an invisible or pale blue flame. sodium chloride. Ca2+ (aq) + Cl- (aq) / Na2C2O4. (i) Calculate the relative formula mass ( Mr) of iron chloride (FeCl3). And to learn why light is shown as the color it is by the excitement of electrons jumping from one shell to the next. Two moles of chlorine and let's find the mass of chlorine on it would be 35.5 grams per mole, three of 3.66 x 20 minutes Times 25 which means you have 1.28 grams of chlorine. How could the identity of the product be verified? Answer (1 of 5): It will be a double displacement reaction leading to the formation of sparingly soluble magnesium hydroxide as a white precipitate. Also when give 3 reduction half reactions, and the molarities of the ions involved, how do you figure out how to separate them and whether or not it is feasible to separate different compounds in the same solution. Identifying an unknown chloride salt by gravimetric analysis Summary Gravimetric analysis will be performed to identify an unknown chloride salt. Given that the cation is from Group 1A, what is the identity of the group 1A metal ion in your solution? Many halide compounds of alkali and alkali earth metals are soluble in water. Does copper and iron chloride react? The density of the water (and the solution) is 1.00 g/mL. What is the identity of the metal? Like all compounds of Sr, this salt emits a bright red colour in a flame; in fact it is used as a source of redness in fireworks. The percentage of the metal in the chlorine-containing compound is "65.95%". Determine the formula of the metal chloride and the accurate atomic weight of . A) Pb B) Ba C) Ca D) K E) none of these 24. Two moles of chlorine and let's find the mass of chlorine on it would be 35.5 grams per mole, three of 3.66 x 20 minutes Times 25 which means you have 1.28 grams of chlorine. The resulting precipitate, filtered and dried, weighs 3.03707 g. What was the percent by mass of chloride ion in the original compound? I m. C 03 has a mass of It's a 2.395 gram sample, and, uh, we're told that chlorine is present in 1.28 grams, so metal em has a massive 1.115 grabs. The student collects the precipitate by filtration, dries it, and records the data shown below. A solution of a trivalent metal ion is electrolysed by a current of 5.0A for 10 minutes during which time 1.18g of metal was plated out. Size and chemical identity of Me-NPs are the main determinants of their toxicity. (Two pieces of evidence are required and one must be related to solubility rules) 3. The bromide of the unknown metal (Metal Br) is dissolved in enough water to make 100mL of solution. We have step-by-step solutions for your textbooks written by Bartleby experts! A student dissolves the chloride of the unknown metal, MCl, in enough water to make 100.0 mL of solution. copper(II)chloride. answered expert verified M+ is an unknown metal cation with a +1 charge. Solutions for Chapter 18 Problem 13P: Electrolysis of an alkaline earth metal chloride using a current of 5.00 A for 748 seconds deposits 0.471 g of metal at the cathode. This effect was even more . Methane reacts with oxygen to form carbon dioxide and water. Safety: Always use good safety techniques. Solution added Observation with solution Y Sulfuric acid A white precipitate forms Magnesium nitrate A white precipitate forms (a) Suggest the identity of the group 2 metal ion present in solution Y. Specific questions: 1. The student then mixes the solution with excess AgNO3 solution, causing AgCl to precipitate. A 4.000-g sample of the metal nitrate M(NO 3) 2 was dissolved in water and treated with excess aqueous sodium sulfate. What is the identity of the metal? Chemical Equations & Stoichiometry. electrolysis of an alkaline earth metal chloride using a current of 5.00 A for 748 seconds deposits 0.471 g of metal at the cathode. All of the chloride is recovered as 1.38 g of silver chloride. Burn the loop end of the wire to remove any dust. 100 ml of the vapour of the chloride of the metal at STP weights 0.72 g. The molecular formula of the metal chloride is: A metal M forms a volatile chloride containing 65.5% chlorine. 1. what is the identity of the alkaline earth metal? A student dissolves the chloride of the unknown metal, MCl, in enough water to make 100.0 mL of solution. This method of analysis allows for a quantitative determination of the mass percent of chlorine in the unknown through precipitation of the chloride ions in the form of silver chloride. 6 H 2 O.Chromium chlorides find use as catalysts and as precursors to dyes for wool. A 1.00-g sample of an alkaline earth metal chloride is treated with A 1.00-g sample of an alkaline earth metal chloride is treated with excess silver nitrate. Cl has a charge of -1. A known amount of the soluble unknown carbonate is dissolved in water to dissociate the compound into ions (Equation 1).